列表推导式 [结果 for循环 if]

字典推导式 {结果(k:v) for循环 if}

集合推导式 {结果(k) for循环 if}

# 生成列表: python1->python18# lst = []# for i in range(1, 19):#     lst.append("python%s期" % i)## print(lst)# 列表推导式 [结果 for循环 if条件]# lst = ["python%s期" % i for i in range(1, 19)]# print(lst)# 生成列表.类表中装的数据是 1-100之间所有的偶数的平方# lst = [i**2 for i in range(1, 101) if i%2 == 0]# print(lst)# 筛选出列表中姓张的同学, lst = ["张无忌", "吴奇隆", "张诗诗", "范冰冰", "张翠山"]# lst = ["张无忌", "吴奇隆", "张诗诗", "范冰冰", "张翠山"]# lst2 = [name for name in lst if name.startswith("张")]# print(lst2)# # 寻找名字中带有两个e的人的名字# names = [['Tom', 'Billy', 'Jefferson', 'Andrew', 'Wesley', 'Steven','Joe'],#         ['Alice', 'Jill', 'Ana', 'Wendy', 'Jennifer', 'Sherry', 'Eva']]## lst = [name for el in names for name in el if name.count("e") == 2]# print(lst)# 字典推导式# 语法: { 结果(key:value) for循环 if条件}# lst = [11,22,33]  # {0:11, 1:22, 2:33}## dic = {i:lst[i] for i in range(len(lst))}# print(dic)# 练习: {"主食": "炒面", "副食": "小拌菜", "汤":"疙瘩汤"}# 把字典的key和value互换, 生成新字典# dic =  {"主食": "炒面", "副食": "小拌菜", "汤":"疙瘩汤"}# d = { v:k for k, v in dic.items()}# print(d)# 集合推导式 {k for循环 if 条件}# 没有元组推导式# g = (i for i in range(10)) # 生成器表达式## print(g)  # 
     
       at 0x0000000009E573B8>## print(g.__next__()) # 0# print(g.__next__()) # 1# print(g.__next__()) # 2# print(g.__next__()) # 3# print(g.__next__()) # 4# print(g.__next__()) # 5# print(g.__next__()) # 6# print(g.__next__()) # 7# print(g.__next__()) # 8# print(g.__next__()) # 9# # print(g.__next__()) # ??? StopIteration### g = (i for i in range(10)) # 生成器表达式# 生成器函数# def func():#     print(111)#     yield 222## # 惰性机制, 只能向前# g = func()  # 创建生成器# g1 = (i for i in g) # 生成器表达式# g2 = (i for i in g1) # 生成器表达式## ## print(list(g1))# print(list(g)) # for -> __next__()# print(list(g2))